12d^2+74d=0

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Solution for 12d^2+74d=0 equation: 



12d^2+74d=0

a = 12; b = 74; c = 0;
Δ = b2-4ac
Δ = 742-4·12·0
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5476}=74$


$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-74}{2*12}=\frac{-148}{24}
=-6+1/6
$


$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+74}{2*12}=\frac{0}{24}
=0
$

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